Swiatek in Doha quarterfinals for the third consecutive time

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Doha. World No. 1 Iga Swiatek continued her impressive winning streak at the Qatar Open by defeating No. 14 seed Ekaterina Alexandrova 6-1, 6-4 in the Round of 16 and reaching the quarterfinals of the tournament for the third consecutive time.

Two-time defending champion Swiatek defeated Alexandrova with a victory of 1 hour and 31 minutes on Wednesday evening and has now won 10 consecutive matches in the tournament.

The Pole will now play two-time Doha champion Victoria Azarenka in the quarterfinals. Former world No. 1 Azarenka defeated No. 8 seed Jelena Ostapenko 6-0, 6-3 in the night match, her third win over Ostapenko this year.

With the victory over world No. 19 Alexandrova, Swiatek has won her last 11 matches against Top 20 opponents, taking her record against that group to 4-0 so far this year. According to the WTA, Swiatek’s last loss to a fellow top 20 member was to Veronika Kudermetova in the Tokyo quarterfinals last September.

Earlier on Wednesday, former world No. 1 Naomi Osaka reached the quarterfinals after her round of 16 opponent, world No. 37 Lesia Tsurenko withdrew from the match due to an elbow injury.

Osaka, who was on maternity leave through the end of 2022 and all of 2023, is through to her first WTA Tour quarterfinal since reaching the Miami Open final in March of 2022.

In the quarterfinals, two-time WTA 1000 titlist Osaka will face another former world No. 1, Karolina Pliskova, who defeated fellow Czech Linda Noskova 3-6, 7-5, 6-1 in three sets.

–IANS

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